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/ * * Bubble algorithm: the score arrays will be sorted from small to large output idea: the first pass sort 1. Compare the n elements in the array, starting with the first element, with the following elements. If the previous data is larger than the later data, and the two swap positions are until a loop is complete, then the largest data in the array will be ranked at the last position in the array. The order of the first round is 3. And so on, the remaining unsorted nmuri elements are similar to the process of 1Power2 again, so that until the end of the loop n times, the elements in the array are sorted from small to large. Note: you only need to go through nmai sorting once * / public class BubbleSort {public static void sort (int [] arrays) {/ / the first cycle control nmai sorting for (int I = 0; I)

Arrays [j + 1]) {int flag = arrays [j]; arrays [j] = arrays [j + 1]; arrays [j + 1] = flag }} public static void main (String [] args) {/ / definition and initialization of one-dimensional array int [] scores = {90, 70, 50, 80, 60, 85}; sort (scores) / / output sorted scores for (int I = 0; I < scores.length; iTunes +) {System.out.print (score [I] + ",");}} about how to understand the bubble sorting algorithm in the Java array. I hope the above content can improve everyone. If you want to learn more knowledge, please pay more attention to the editor's updates. Thank you for following the website!

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