How to create a hollow diamond with a two-dimensional array by Java

In this article Xiaobian introduces in detail for you "Java how to create a hollow diamond with a two-dimensional array" with detailed content, clear steps and proper handling of details. I hope this article "Java how to create a hollow diamond with a two-dimensional array" can help you solve your doubts.

How to create a hollow diamond with a two-dimensional array

Provide my own implementation method, the realization of the method is only a person's way, not on behalf of strength, the real strength to use their own thinking to solve other people's urgent problems, is really the meaning of programming. I feel refreshed after drinking the chicken soup. Let's take a look at my example.

Topic: create a diamond hollow with "*"

In order to better find out the relationship between horizontal and vertical coordinates, I simply made a diamond diagram.

Figure 1. Diamond shape

The meaning of * points and coordinate values can be found from the diagram, so this problem is done with two-dimensional coordinates.

The output image is divided into two parts, and the upper part:

Blossom from the middle, assign the value on both sides to 1, otherwise it is 0, and finally output the * sign to the point assigned to 1.

Defines the bit int [] a=new int [13] [13] of a two-dimensional array

Define two points in the column direction, p1 and p2, that is, a [I] [p1], a [I] [p2]

So from figure 2, you can see that point An and BMagne C can tell p1=a.length/2-i (in the programming process, I is 0grade. recall 2 is also the midpoint of a line), p2centa.bearthbind 2quoi; B (iMaginp1), C (iMaginp2)

Figure 2. Diamond shape

Why is it divided into two parts? because in a.lengh/2-i, it is negative when I equals 7, so we can't always use the original value of p1 and p2. We need to find the law of horizontal and vertical coordinates again.

The second half:

The coordinate of D is (igravium italk a.paradthbin2), that is, D (irecoverp3), and the coordinate of E is more difficult to find the relationship. I also thought about it for a long time. Ha ha, I just kept trying, but in the end, I couldn't try it out. It was only by drawing and analyzing that I could find the rule. So the scientific method is to use mathematical thinking to find the position relationship of horizontal and vertical coordinate points.

Fig. 3 coordinate analysis of point E

Specific implementation code:

Package com.JavaBase; public class lingxing {/ / rhomboid public static void main (String [] args) {int n = 15 * (int +) {a [I] [j] = 0; int p1 = a.length / 2-I; int p2 = a [I] .length / 2 + I Tinct hand p1 and p2 is very easy to find if (I