How to judge whether a file exists in python

This article shows you how to judge the existence of a file in python, the content is concise and easy to understand, it can definitely brighten your eyes. I hope you can get something through the detailed introduction of this article.

Method 1, os.path.exists import os

Print (os.path.exists ('log.txt'))

This is my favorite method. It can judge not only whether a file exists, but also whether a folder exists. Method 2, os.path.isfile import os

Print (os.path.isfile ('log.txt'))

The isfile method can determine whether the given path is a file, and if so, it proves that the file exists, otherwise, the file does not exist. Method 3, try to open the file try in read mode:

With open ('log.txt', 'r') as fh:

Pass

Except FileNotFoundError:

Print ('does not exist')

If the file does not exist, a FileNotFoundError exception will be thrown, and the existence of the file can be judged by catching the exception by except. The with keyword is used to open the file, so there is no need to actively close the file method 4, use pathlib from pathlib import Path

Config = Path ('log.txt')

Print (config.is_file ())

The principle is the same as os.path.isfile.

The above is how to determine the existence of a file in python. Have you learned the knowledge or skills? If you want to learn more skills or enrich your knowledge reserve, you are welcome to follow the industry information channel.