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This article mainly introduces LeetCode how to find n dice points, has a certain reference value, interested friends can refer to, I hope you can learn a lot after reading this article, the following let the editor take you to understand it.

Topic description

Throw n dice on the ground and the sum of the points on one side of all the dice is s. Enter n to print out the probability of occurrence of all possible values of s.

You need to return the answer with a floating-point array, where the I element represents the probability of the smaller I of the set of points that the n dice can throw.

1 probability dictionary. Initialize dp [0] = 1. The probability that the sum of points is 0 for 0 dice is 1.

# after adding a dice, we only need to add 1x 6 to the sum of each point in the original dictionary as the sum of the new points, and multiply the original probability by 1 stroke 6 to add to the new points and the corresponding probability

Dp = {}

Dp [0] = 1

For i in range (1, n + 1):

Newdp = collections.defaultdict (int)

For sm in dp:

For v in range (1,7):

# after adding a dice, add its probability to the new point sum

Newdp [sm + v] + = dp [sm] / 6

Dp = newdp

Res = []

For sm in range (n, 6 * n + 1):

# store the values in the result in turn

Res.append (dp[ sm])

Return res

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