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This article mainly shows you "java how to achieve wobble sorting", the content is easy to understand, clear, hope to help you solve your doubts, the following let the editor lead you to study and learn "java how to achieve wobble sorting" this article.

Given an unordered array nums, rearrange it into nums [0]

Nums [2]

> 1

3 int [] copy = Arrays.copyOf (nums, n)

4 Arrays.sort (copy)

5 for (int I = m-1, j = 0; I > = 0; imuri, j + = 2)

6 nums [j] = copy [I]

7 for (int I = n-1, j = 1; I > = m; imuri, j + = 2)

8 nums [j] = copy [I]

9}

Parsing:

First copy the nums into another array copy, and then sort the copy array. Here, the first half of the copy array is first inserted from back to front into the even digits of the array nums subscript (the subscript starts at 0), and then the second half of the array copy is inserted into the odd digits of the array nums subscript from back to front, because the array copy is sorted. So the value in the array nums will be that the value in the odd digit of the subscript is greater than its previous and latter one, and the value in the even digit of the subscript will be less than its previous and latter value. We can also write it differently.

1public void wiggleSort (int [] nums) {

2 int [] copy = Arrays.copyOf (nums, nums.length)

3 Arrays.sort (copy)

4 int n = nums.length

5 int left = (n + 1) / 2-1; / / intermediate index

6 int right = n-1; / / Index of the maximum value

7 for (int I = 0; I < nums.length; iTunes +) {

8 if (I% 2 = = 1) {

9 nums [I] = copy [right]

10 right--

11} else {

12 nums [I] = copy [left]

13 left--

14}

15}

16}

Although there is a slight difference in writing, the principle is still the same.

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