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Editor to share with you how to calculate the integer power of LeetCode, I believe that most people do not know much about it, so share this article for your reference, I hope you can learn a lot after reading this article, let's go to know it!

1. Brief introduction of the problem.

Realize the function double Power (double base, int exponent) and find the exponent power of base. Library functions are not allowed, and large numbers do not need to be considered.

2, example

Example 1:

Input: 2.00000, 10 output: 1024.00000 example 2:

Input: 2.10000, 3 output: 9.26100 example 3:

Input: 2.00000,-2 output: 0.25explanation: 2-2 = 1max 22 = 1max 4 = 0.25000

Description:

-100.0

< x < 100.0n 是 32 位有符号整数，其数值范围是 [−231, 231 − 1] 。 3，题解思路 快速幂方法，java已有的api两种方法 4，题解程序 public class MyPowTest { public static void main(String[] args) { double x = 2.00000; int n = 10; double myPow = myPow(x, n); System.out.println("myPow = " + myPow); } public static double myPow(double x, int n) { if (x == 0) { return 0; } if (n == 0) { return 1; } if (n >

0) {return pow (x, n);} else {return pow (1 / x,-n);}}

Private static double pow (double x, int n) {if (n = = 0) {return 1;} double r = pow (x, n / 2); if ((n & 1) = = 1) {return r * r * x;} else {return r * r;}

5. Picture version of the problem solving program.

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