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The method and steps of how to filter the array in the document by mongodb

2025-01-17 Update From: SLTechnology News&Howtos shulou NAV: SLTechnology News&Howtos > Database >

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This article introduces the methods and steps of how to filter the array in the document by mongodb and shares them with you. The details are as follows:

The mongodb document contains an array, and you need to filter out the eligible data in the array and return the result set. You can query group or filter in two ways.

Data source:

{"_ id": ObjectId ("5bbcc0c9a74db9804e78a157"), "uid": "1000001", "name": "zhangsan", "addrs": [{"is_query": "1", "city": "Beijing"}, {"is_query": "0", "city": "Shanghai"} {"is_query": "1", "city": "Shenzhen"}} {"_ id": ObjectId ("5bbcc167a74db9804e78a172"), "uid": "1000002", "name": "lisi", "addrs": [{"is_query": "0", "city": "Beijing"} {"is_query": "0", "city": "Shanghai"}, {"is_query": "1", "city": "Shenzhen"]}

The query is required to specify that under uid, the addrs array contains only the result set with is_query equal to 1 (not included in 0).

Query statement:

Method 1: use $unwind to break up the addrs array, get the result set, filter the eligible data with $match, and finally aggregate the final result set using $group.

Db.getCollection ('user') .aggregate ([{$unwind: "$addrs"}, {$match: {"uid": "1000001", "addrs.is_query": "1"}}, {$group: {"_ id": "$uid" "addrs": {$push: "$addrs"}])

Result:

{"_ id": "1000001", "addrs": [{"is_query": "1", "city": "Beijing"}, {"is_query": "1", "city": "Shenzhen"}]}

Method 2: use $match to filter the eligible root document result set, and then use $project to return the corresponding field, while using $filter in the addrs array to filter internally to return the final result set

Db.getCollection ('user') .aggregate ([{$match: {"uid": "1000001"}}, {$project: {"uid": 1, "name": 1, "addrs": {$filter: {input: "$addrs", as: "item" Cond: {$eq: ["$$item.is_query", "1"]}}])

Result:

{"_ id": ObjectId ("5bbcc0c9a74db9804e78a157"), "uid": "1000001", "name": "zhangsan", "addrs": [{"is_query": "1", "city": "Beijing"}, {"is_query": "1", "city": "Shenzhen"}]}

Compared to the way the $group group aggregate returns the result set, $filter is more elegant and straightforward under the current query requirements. Of course, if you include statistical operations, such as requiring that the number of is_query equal to 1 is returned, then $group is very appropriate.

The above is the whole content of this article, I hope it will be helpful to your study, and I also hope that you will support it.

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