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How to use java to solve the problem of affinity number

2025-02-25 Update From: SLTechnology News&Howtos shulou NAV: SLTechnology News&Howtos > Internet Technology >

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This article is about how to use java to solve the affinity problem. The editor thinks it is very practical, so share it with you as a reference and follow the editor to have a look.

Note that d (n) is the sum of all true factors of n (positive integers less than n and divisible n).

If d (a) = b and d (b) = a, and a ≠ b, then an and b form an affinity pair, and an and b are called affinity numbers.

For example, the true factor of 220 includes 1, 2, 4, 5, 10, 11, 20, 22, 44, 55 and 100, so d (220) = 284, while the true factor of 284 includes 1, 2, 4, 71 and 142, so d (284) = 220.

Find the sum of all affinity numbers less than 10000.

System.out.println (factorialDigitSum)

Analysis:

Neither int nor long can be represented, so if you want to use BinInteger, it's easy not to introduce it.

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