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How java uses dichotomy to find specified elements in an array

2025-01-16 Update From: SLTechnology News&Howtos shulou NAV: SLTechnology News&Howtos > Development >

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This article is about how java uses binary to find specified elements in an array. The editor thinks it is very practical, so share it with you as a reference and follow the editor to have a look.

Search for specified elements in an array (binary search) A necessary condition for binary search is an ordered sequence of public static int binarySearch (int [] array,int key) {int left = 0; int right = array.length-1; while (left key) {right = mid-1;} else if (array [mid])

< key){ left = left + 1; }else{ return mid; } } return -1; } public static void main(String[] args) { int[] array = {12,14,15,16,18,23}; System.out.println(binarySearch(array, 15)); } 打印结果:

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