Shulou(Shulou.com)06/03 Report--

This article will explain in detail why there is no function overloading in python. The editor thinks it is very practical, so I share it for you as a reference. I hope you can get something after reading this article.

1. When we define multiple functions with the same name, the latter function always overrides the previous function.

So in a namespace, there is only one registration entry for each function name.

2. When the program is running, if it encounters another function with the same name, it will update the registration project in the local namespace.

Thus the possibility of coexistence of the two functions is eliminated.

Therefore, Python does not support function overloading. This is a design decision when creating a language, but it doesn't prevent us from implementing it.

Note: it is said here that Python does not support function overloading, which means that Python does not use syntax sugar. Using the singledispatch decoration of the functools library, Python can also implement function overloading. This is specifically mentioned by the original author in his notes at the end of the article.

By calling the locals () and globals () functions, you can see what the namespace of Python is, returning the local and global namespaces, respectively.

Def area (radius): return 3.14 * radius * * 2 > > locals () {. 'area':,...}

After defining a function and then calling the locals () function, we will see that it returns a dictionary, including all variables defined in the local namespace. The dictionary key is the name of the variable and the value is the reference / value of the variable.

This is the end of the article on "Why there is no function overloading in python". I hope the above content can be of some help to you, so that you can learn more knowledge. if you think the article is good, please share it for more people to see.

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