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This article introduces the relevant knowledge of "an example Analysis of the visibility of java". In the operation of actual cases, many people will encounter such a dilemma, so let the editor lead you to learn how to deal with these situations. I hope you can read it carefully and be able to achieve something!

Test1:

Volatile is added to the test1 example, so the program exits the output test1 end correctly

Test2:

Test2 this example does not add volatile, the program also normal exit and output a bunch of 0 and output test2 end, this is why? Why is there visibility without volatile? It seems like a weird question, but the problem is to add a line of System.. to the while. Output problem, open the source code to see the println method to add a synchronized synchronization block, it is precisely because this synchronization block ensures the visibility of the variable x, this strange problem is solved.

Test3:

In the case of test3, there is neither volatile nor System.. in while. Output statement, so the thread's modification of variable n3 is not visible to the main thread, the program loops all the time, and there is no output.

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