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This article will explain in detail how to call the general method of WebApi. The editor thinks it is very practical, so I share it with you as a reference. I hope you can get something after reading this article.

WebApi may have a variety of problems when passing basic parameters, some need to add [FromBody] features on the server side, some need to add a layer of encapsulation into entities, and some use dynamic types. Through the WebClient class. The code is as follows, and you just need to add any parameters in QueryString.

Try {WebClient client = new WebClient (); / / client.QueryString.Add ("account", "Feng Bao"); / / client.QueryString.Add ("password", "7777"); client.QueryString.Add ("name", "Feng Bao"); client.Encoding = Encoding.UTF8 Client.Headers.Add (HttpRequestHeader.ContentType, "application/json"); / / string result = client.UploadString ("http://localhost:51151/Api/Users/Login","); string result = client.UploadString (" http://localhost:51151/Api/Users/WithStringParamNoFromBody", "") } catch (Exception ex) {}

The backend WebApi code is as follows:

[AllowAnonymous] [HttpPost] public IEnumerable WithStringParamNoFromBody (string name) {return _ userList } [AllowAnonymous] [HttpPost] public string Login (string account, string password) {if (account.Equals ("Feng Bao") & & password.Equals ("7777")) {FormsAuthenticationTicket ticket = new FormsAuthenticationTicket (0, account, DateTime.Now) DateTime.Now.AddMinutes (5), true, $"{account} & {password}", FormsAuthentication.FormsCookiePath) Var result = new {Result = true, Ticket = FormsAuthentication.Encrypt (ticket)}; return JsonConvert.SerializeObject (result);} else {var result = new {Result = false}; return JsonConvert.SerializeObject (result) }} this is the end of the article on "how to call the General method of WebApi". I hope the above content can be of some help to you, so that you can learn more knowledge. if you think the article is good, please share it for more people to see.

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