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This article will explain in detail how to calculate the product of two matrices in C language. The content of the article is of high quality, so the editor shares it for you as a reference. I hope you will have some understanding of the relevant knowledge after reading this article.

Analysis.

In mathematics, matrix (Matrix) is a set of complex or real numbers arranged according to a rectangular array. Matrix is a common tool in higher algebra, and it is also common in applied mathematics subjects such as statistical analysis.

The multiplication of matrices has the following considerations:

1. When the number of columns of matrix A (column) is equal to the number of rows of matrix B (row), An and B can be multiplied.

2. The number of rows of matrix C is equal to the number of rows of matrix A, and the number of columns of C is equal to the number of columns of B.

3. The element of the m-th row and the nth column of the product C is equal to the sum of the product of the m-th row of the matrix An and the nth column of the matrix B.

Code implementation: only need to use the matrix product formula to find a new matrix, that is, the product of two matrices, the program also needs to determine whether the input of the two matrices can be multiplied.

Code implementation # include int main () {int line_a = 0; / A matrix rows int col_a = 0; / A matrix rows int line_b = 0; / B matrix rows int col_b = 0; / / B matrix columns int I = 0; int j = 0; int k = 0 / * get the number of rows and columns of A matrix * / printf ("Please enter the number of rows and columns of A matrix\ n"); scanf ("% d% d", & line_a, & col_a); int matrix_ A [line _ a] [col_a]; / * get the number of rows and columns of B matrix * / printf ("Please enter the number of rows and columns of B matrix\ n") Scanf ("% d% d", & line_b, & col_b); int matrix_ B [line _ b] [col_b]; if (col_a! = line_b) {printf ("the number of columns of the error,A matrix and the number of rows of the B matrix must be equal! \ n "); return 0;} int matrix_ C [line _ a] [col_b]; / / C matrix: product of A matrix and B matrix / * get A matrix elements * / for (I = 0; I < line_a; iTunes +) {printf (" Please enter% d row elements of A matrix\ n ", I); for (j = 0; j < col_a) Scanf ("% d", & matrix_ A [I] [j]);}} / * get B matrix elements * / for (I = 0; I < line_b; iMatrix +) {printf ("Please enter% d row elements of B matrix\ n", I); for (j = 0; j < col_b) For +) {scanf ("% d", & matrix_ B [I] [j]);}} / * print matrix * / printf ("input A matrix is:\ n"); for (I = 0; I < line_a; iTunes +) {for (j = 0; j < col_a) Printf +) {printf ("% d\ t", matrix_ A [I] [j]);} printf ("\ n");} printf ("input B matrix is:\ n"); for (I = 0; I < line_b; iMatrix +) {for (j = 0; j < col_b) Printf +) {printf ("% d\ t", matrix_ B [I] [j]);} printf ("\ n");} / * find the product of AB, that is, matrix C * / for (I = 0; I < line_a; iTunes +) {for (j = 0; j < col_b; jacks +) {matrix_ C [I] [j] = 0 / initialize for (k = 0; k < col_a; knot +) matrix_ C [I] [j] + = matrix_ A [I] [k] * matrix_ B [k] [j];}} / * print C matrix * / printf ("A matrix multiplied B matrix:\ n"); for (I = 0; I < line_a; iMatrix +) {for (j = 0) J < col_b; jacks +) {printf ("% d\ t", matrix_ C [I] [j]);} printf ("\ n");} return 0;}

Running result

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