How to use Shell script to count the number of directories and files in the current directory
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Write a script in shell, place it in the current directory, and execute it.
The code is as follows:
#! / bin/bash
# script name dir
# define a function fun_directory
Fun_directory () {
Let "filenum=0"
Let "dirnum=0"
For i in $(ls)
Do
If [- d $I]
Then
Let dirnum+=1
Else
Let filenum+=1
Fi
Done
Echo "The number of directorys is $dirnum"
Echo "The number of files is $filenum"
}
# call function
Fun_directory
Let's test it:
The code is as follows:
[root@localhost scripts] # pwd
/ root/scripts
[root@localhost scripts] # ll | sort
Drwxr-xr-x 2 root root 4096 06-12 10:44 charpter8
Drwxr-xr-x 2 root root 4096 06-13 12:34 aaa
-rw-r--r-- 1 root root 105 06-13 08:56 file1
-rw-r--r-- 1 root root 106 06-12 14:24 8-9
-rw-r--r-- 1 root root 121 06-12 09:36 jiu
-rw-r--r-- 1 root root 133 06-13 11:09 temp
-rw-r--r-- 1 root root 210 06-12 13:40 8-8
-rw-r--r-- 1 root root 2222 06-12 11:51 8-6
-rw-r--r-- 1 root root 247 06-12 11:35 8-5
-rw-r--r-- 1 root root 273 06-12 13:13 8-7
-rw-r--r-- 1 root root 292 06-12 10:57 8-1
-rw-r--r-- 1 root root 309 06-12 14:51 8-11
-rw-r--r-- 1 root root 314 06-12 15:01 8-17
-rw-r--r-- 1 root root 317 06-13 12:10 test
-rw-r--r-- 1 root root 51 06-12 11:00 8-2
-rw-r--r-- 1 root root 53 06-13 08:51 file
-rw-r--r-- 1 root root 67 06-13 10:17 10-4
-rw-r--r-- 1 root root 78 06-13 10:09 test.out
-rwxr-xr-x 1 root root 103 06-12 11:06 8-3
-rwxr-xr-x 1 root root 124 06-13 10:02 10-32
-rwxr-xr-x 1 root root 304 06-13 12:47 dir
-rwxr-xr-x 1 root root 316 06-12 11:21 8-4
# execute script
[root@localhost scripts] # sh dir
The number of directorys is 2
The number of files is 20
[root@localhost scripts] #
As you can see, the statistics are accurate.
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