How to use the int () method in operator
This article will explain in detail how to use int() method in operator. The content of the article is of high quality, so Xiaobian shares it with you as a reference. I hope you have a certain understanding of relevant knowledge after reading this article.
operator int() is a type conversion operator, such as:
struct A
{
int a;
A(int i):a(i){}
operator int() const { return a; }
};
void main()
{
A aa(1);
int i = int(aa);
int j = aa; //same effect
}
The return value type of this function is the function name, so there is no need to express it explicitly.
What do you mean return type is function name?
============================
The return type is int, and the function name is int, that is, it is not written as int operator int() const { return value; },
The return type is omitted.
operator int() is a conversion operator, which allows this class to be used in place of an int. If an object of this type is used in a place where an int (or other numerical type) is expected, then this code will be used to get a value of the correct type.
For example:
int i(1);
INT I(2); // Initialised with constructor; I.a == 2
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