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This article will explain in detail how to use int() method in operator. The content of the article is of high quality, so Xiaobian shares it with you as a reference. I hope you have a certain understanding of relevant knowledge after reading this article.

operator int() is a type conversion operator, such as:

struct A

{

int a;

A(int i):a(i){}

operator int() const { return a; }

};

void main()

{

A aa(1);

int i = int(aa);

int j = aa; //same effect

}

The return value type of this function is the function name, so there is no need to express it explicitly.

What do you mean return type is function name?

============================

The return type is int, and the function name is int, that is, it is not written as int operator int() const { return value; },

The return type is omitted.

operator int() is a conversion operator, which allows this class to be used in place of an int. If an object of this type is used in a place where an int (or other numerical type) is expected, then this code will be used to get a value of the correct type.

For example:

int i(1);

INT I(2); // Initialised with constructor; I.a == 2

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