How to solve the problem of $_ server [server _ NAME] of PHP

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problem

The jump link when the official account of Wechat acquires code. The default is to get the link of the current page. The code is as follows:

/ / description: get the url address function GetCurrentpageURL () {$pageURL = 'http'; if ($_ SERVER ["HTTPS"] = = "on") {$pageURL. = "s";} $pageURL. = ": / /"; if ($_ SERVER ["SERVER_PORT"]! = "80") {$pageURL. = $_ SERVER ["SERVER_NAME"]. ":" $SERVER ["SERVER_PORT"]. $_ SERVER ["REQUEST_URI"];} else {$pageURL. = $_ SERVER ["SERVER_NAME"]. $_ SERVER ["REQUEST_URI"];} / / echo $SERVER ["SERVER_NAME"] .PHP_EOL;// echo $pageURL;die; return $pageURL;}

Now I want to add a domain name. I appended this domain name under the conf file on Nginx, as follows:

Server {listen 80; server_name origin.baidu.com back.baidu.com; / / something

After adding the domain name and setting the authorized domain name, visit http://back.baidu.com?xxx and be redirected to http://origin.baidu.com/xxx each time.

Solution.

OK, I know there is a problem with the current link obtained by the function that gets the current domain name. In the conf file of Nginx, bring back.baidu.com to the front, and the problem is solved.

Server {listen 80; server_name back.baidu.com origin.baidu.com; / / something

Reason

The $_ SERVER ["SERVER_NAME"] of PHP does not get the domain name on the address bar, but the first domain name in the configuration file.

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