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This article shows you the solution to the problem of java multithreading, which is concise and easy to understand, which will definitely brighten your eyes. I hope you can get something through the detailed introduction of this article.

See a multi-threaded topic on iteye, with reference to the implementation of netizens, then Eclipse debugging passed, can be regarded as a general understanding of the concurrent library of JAVA5, share it, welcome the students in the park to beat bricks.

Title:

It is required to use three threads to print 1, 2, 3, 4, 5 in order. 71,72,73,74, 75.

Thread 1 prints 1, 2, 3, 4, 5, 2, 6, 7, 8, 9, 10, and then thread 3 prints 11, 12, 13, 14, 15. Then thread 1 prints 16, 17, 18, 19, 20. And so on until thread 3 prints to 75.

Analysis: I feel that the person who asks the question is to see if you can control the multithreading well and let them proceed in an orderly manner.

1. Thread pool: 3 threads, which need to use the thread pool of the concurrent library

2. Lcok: when printing, only one thread is allowed to enter, while other threads wait

The following is the main code:

Import java.util.HashMap; import java.util.Map; import java.util.concurrent.CountDownLatch; import java.util.concurrent.ExecutorService; import java.util.concurrent.Executors; import java.util.concurrent.locks.Condition; import java.util.concurrent.locks.Lock; import java.util.concurrent.locks.ReentrantLock; public class NumberPrinter {private Lock lock = new ReentrantLock (); private Condition C1 = lock.newCondition (); private Condition c2 = lock.newCondition () Private Condition c3 = lock.newCondition (); private Map condtionContext = new HashMap (); public NumberPrinter () {condtionContext.put (Integer.valueOf (0), C1); condtionContext.put (Integer.valueOf (1), c2); condtionContext.put (Integer.valueOf (2), c3);} private int count = 0 Public void print (int id) {lock.lock (); try {while (count*5 < 75) {int curID = calcID (); if (id = = curID) {for (int I = 1; I)

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