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This article will explain in detail how to draw a fish countdown interface based on Python. The editor thinks it is very practical, so I share it with you as a reference. I hope you can get something after reading this article.

Realization process

First of all, I need to know that in addition to static text, such as the current date, the number of days away from the holiday, and so on, are returned dynamically, I need to use the Jinja2 template for dynamic binding.

I should focus on the management of time.

And in this template, there are solar calendar festivals, but also lunar calendar festivals, I need to convert.

Initialize a FastAPI object and declare the template directory of the static page (Jinja2Templates)

#-*-coding: utf-8-*-import datetime from fastapi import FastAPI, Request from fastapi.responses import HTMLResponse from fastapi.templating import Jinja2Templates from zhdate import ZhDate as lunar_date app = FastAPI (debug=False, title= "My API", docs_url= "/ docs", openapi_url=f "/ openapi.json") templates = Jinja2Templates (directory= "templates")

What you can see is that I used the zhdate library, which is mainly used for the conversion between the lunar calendar and the solar calendar. The usage is as follows

Today = datetime.date.today () print (today.year, today.month, today.day) print ("Big year time:", lunar_date (today.year+1, 1,1). To_datetime (). Date () print ("Dragon Boat Festival time:", lunar_date (today.year, 5,5). To_datetime (). Date () print ("Mid-Autumn Festival time:", lunar_date (today.year, 8) 15). To_datetime (). Date () print ("New Year's Day time:", f "{today.year+1}-01-01") print ("Ching Ming time:", f "{today.year}-04-05") print ("working time:", f "{today.year}-05-01") print ("National Day time:", f "{today.year}-10-01")

We can sort it out:

When calculating the days from Da Nian and New Year's Day, you should add 1 to the year.

When calculating the number of days from other festivals, it is necessary to determine whether the difference in days is less than 0, and if so, the year needs to be + 1, because past festivals have no meaning to it.

Distance_big_year = (lunar_date (today.year + 1,1,1). To_datetime (). Date ()-today). Days distance_5_5 = (lunar_date (today.year, 5,5). To_datetime (). Date ()-today). Days distance_5_5 = distance_5_5 if distance_5_5 > 0 else (lunar_date (today.year + 1,5) 5). To_datetime (). Date ()-today). Days distance_8_15 = (lunar_date (today.year, 8,15). To_datetime (). Date ()-today). Days distance_8_15 = distance_8_15 if distance_8_15 > 0 else (lunar_date (today.year + 1,8) 15). To_datetime (). Date ()-today). Days distance_year = (datetime.datetime.strptime (f "{today.year + 1}-01-01", "% Y-%m-%d"). Date ()-today). Days distance_4_5 = (datetime.datetime.strptime (f "{today.year}-04-05") "% Y-%m-%d") .date ()-today) .days distance_4_5 = distance_4_5 if distance_4_5 > 0 else (datetime.datetime.strptime (f "{today.year + 1}-04-05", "% Y-%m-%d") .date ()-today) .days distance_5_1 = (datetime.datetime.strptime (f "{today.year}-05-01") "% Y-%m-%d") .date ()-today) .days distance_5_1 = distance_5_1 if distance_5_1 > 0 else (datetime.datetime.strptime (f "{today.year + 1}-05-01", "% Y-%m-%d") .date ()-today) .days distance_10_1 = (datetime.datetime.strptime (f "{today.year}-10-01") "% Y-%m-%d") .date ()-today) .days distance_10_1 = distance_10_1 if distance_10_1 > 0 else (datetime.datetime.strptime (f "{today.year + 1}-10-01", "% Y-%m-%d") .date ()-today) .days

How's it going? My name is crazy enough.

Next, you need to calculate the number of days from the weekend.

Def get_week_day (date): week_day_dict = {0: Monday, 1: Tuesday, 2: Wednesday, 3: Thursday, 4: Friday, 5: Saturday, 6: Sunday } day = date.weekday () return week_day_ today [day] week_day_ = get_week_day (today) print (f "today is: {week_day_}") # get what day it is today

According to the five working days a week, the number of days from today to the weekend is

5-today.weekday () # today.weekday () Today is from the weekend

Now put all the data together.

Time_ = [{"v_": distance_year, "title": "New Year's Day"}, # distance to New Year's Day {"v_": distance_big_year, "title": "Chinese New year"}, # distance to Spring Festival {"v_": distance_4_5, "title": "Ching Ming Festival"}, # distance to Qingming {"v_": distance_5_1 "title": "International Labour Day"}, # distance from labor {"v_": distance_5_5, "title": "Dragon Boat Festival"}, # distance to Dragon Boat Festival {"v_": distance_8_15, "title": "Mid-Autumn Festival"}, # distance to Mid-Autumn Festival {"v_": distance_10_1, "title": "National Day"}, # distance to National Day]

As for why List instead of Dict, I need to do a ranking according to the number of days away, so that the first holiday comes first, so it will look much more comfortable.

Time_ = sorted (time_, key=lambda x: X ['vested'], reverse=False)

The next step is to write a route that passes the data into the html page.

@ app.get ("/", response_class=HTMLResponse) async def readme (request: Request): return templates.TemplateResponse ("readme.html", {"request": request, "time_": time_, "now_": now_, "week_day_": week_day_})

Take a look at the complete code (main.py):

#-*-coding: utf-8-*-import datetime from fastapi import FastAPI, Request from fastapi.responses import HTMLResponse from fastapi.templating import Jinja2Templates from zhdate import ZhDate as lunar_date app = FastAPI (debug=False, title= "My API", docs_url=f "/ docs", openapi_url=f "/ openapi.json") templates = Jinja2Templates (directory= "templates") today = datetime.date.today () # print (today.year, today.month, today.day) # print Lunar_date (today.year+1, 1,1). To_datetime (). Date () # print ("Dragon Boat Festival time:", lunar_date (today.year, 5,5). To_datetime (). Date () # print ("Mid-Autumn Festival time:", lunar_date (today.year, 8,15). To_datetime (). Date () # print ("New Year's Day time:" F "{today.year+1}-01-01") # print ("Ching Ming time:", f "{today.year+1}-04-05") # print ("working time:", f "{today.year+1}-05-01") # print ("National Day time:", f "{today.year+1}-10-01") distance_big_year = (lunar_date (today.year+1, 1) 1). To_datetime (). Date ()-today). Days distance_5_5 = (lunar_date (today.year, 5,5). To_datetime (). Date ()-today). Days distance_5_5 = distance_5_5 if distance_5_5 > 0 else (lunar_date (today.year + 1,5,5). To_datetime (). Date ()-today). Days distance_8_15 = (lunar_date (today.year, 8) 15). To_datetime (). Date ()-today). Days distance_8_15 = distance_8_15 if distance_8_15 > 0 else (lunar_date (today.year + 1,8,15). To_datetime (). Date ()-today). Days distance_year = (datetime.datetime.strptime (f "{today.year + 1}-01-01") "% Y-%m-%d") .date ()-today) .days distance_4_5 = (datetime.datetime.strptime (f "{today.year}-04-05", "% Y-%m-%d") .date ()-today) .days distance_4_5 = distance_4_5 if distance_4_5 > 0 else (datetime.datetime.strptime (f "{today.year + 1}-04-05") "% Y-%m-%d") .date ()-today) .days distance_5_1 = (datetime.datetime.strptime (f "{today.year}-05-01", "% Y-%m-%d") .date ()-today) .days distance_5_1 = distance_5_1 if distance_5_1 > 0 else (datetime.datetime.strptime (f "{today.year + 1}-05-01") "% Y-%m-%d") .date ()-today) .days distance_10_1 = (datetime.datetime.strptime (f "{today.year}-10-01", "% Y-%m-%d") .date ()-today) .days distance_10_1 = distance_10_1 if distance_10_1 > 0 else (datetime.datetime.strptime (f "{today.year + 1}-10-01") "% Y-%m-%d") .date ()-today) .days def get_week_day (date): week_day_dict = {0: Monday, 1: Tuesday, 2: Wednesday, 3: Thursday, 4: Friday, 5: Saturday Day = date.weekday () return week_day_ Sunday # print ("distance from Lunar New year:", distance_big_year) # print ("distance to Dragon Boat Festival:", distance_5_5) # print ("distance to Mid-Autumn Festival:", distance_8_15) # print ("distance to New Year's Day:", distance_year) # print ("distance to Qingming Festival:" Distance_4_5) # print ("distance to work:", distance_5_1) # print ("distance to National Day:", distance_10_1) # print ("distance weekend:", 5-today.weekday ()) now_ = f "{today.year} month {today.day} day" week_day_ = get_week_day (today) time_ = [{"v _": 5-1-today.weekday () "title": "weekend"}, # distance from weekend {"v _": distance_year, "title": "New Year's Day"}, # distance from New Year's Day {"v _": distance_big_year, "title": "Chinese New year"}, # distance from Chinese New year {"v_": distance_4_5, "title": "Ching Ming Festival"} # distance from Qingming Festival {"v _": distance_5_1, "title": "International Labour Day"}, # distance from labor {"v _": distance_5_5, "title": "Dragon Boat Festival"}, # distance from Dragon Boat Festival {"v _": distance_8_15, "title": "Mid-Autumn Festival"}, # distance from Mid-Autumn Festival {"v_": distance_10_1 "title": "National Day"}, # distance to National Day] time_ = sorted (time_, key=lambda x: X ['vested'], reverse=False) @ app.get ("/", response_class=HTMLResponse) async def readme (request: Request): return templates.TemplateResponse ("readme.html", {"request": request, "time_": time_, "now_": now_ "week_day_": week_day_}) if _ _ name__ = ='_ main__': import uvicorn uvicorn.run (app='main:app', host= "0.0.0.0", port=8080, reload=True)

Finally, coming to the html page section, let's take a look at the main values passed.

[fish fishing Office] Today is {{now_}} {{week_day_}}

{% for v _ in time_%}

? There are still {{v_.title. V _}} days away from the holiday.

{% else%}

No value at all

{% endfor%}

In this way, the entire route construction and page writing is complete.

Finally, it is deployed to my site through Nginx.

This is the end of this article on "how to draw a fish countdown interface based on Python". I hope the above content can be of some help to you, so that you can learn more knowledge. if you think the article is good, please share it for more people to see.

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