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This article introduces the knowledge of "how to use Python to write an incremental function of a string number suffix". In the operation of actual cases, many people will encounter such a dilemma, so let the editor lead you to learn how to deal with these situations. I hope you can read it carefully and be able to achieve something!

Demand:

Python handles duplicate name strings, adding or incrementing numeric string suffixes

For 2 duplicate strings, add a numeric suffix, such as two duplicate strings S1 = "name", S2 = "name", and set the name of S2 to name_1

Corresponding to 3 or more strings with duplicate names, the number is incremented. At the beginning, S1 = "name" is renamed to get S1 = "name", S2 = "name_1", S3 = "name_2".

To deal with string problems flexibly, it is most convenient to use re module.

Here is a way to increment a suffix string with an underscore + number

Def increase_string_suffix (s, incr_num=1):

"

String self-increment method with numeric suffix "_ d", "name_1" self-increment 1-- > "name_2"

Example

-

> s = "name_01"

> increase_string_suffix (s, incr_num=2)

'name_03'

"

Suffix_searched = re.search (r "(_) (\ d +) $", s)

If suffix_searched:

Suffix_plus_1 = re.sub (

R "(_) (\ d +) $"

Lambda x: F "{x.group (1)} {str (int (x.group (2)) + incr_num) .zfill (len (x.group (2)}"

S

)

Else:

Suffix_plus_1 = f "{s} _ 1"

Return suffix_plus_1

The example can run the doc part of the comment directly in the code, the parameter s is the string to be passed in, and incr_num is the number of steps to be increased at a time

The core part of the code is the re.sub method, r "(_) (\ d +) $" is the matching search part, () the matching part is grouped, x.group (1) is () matched to "", x.group (2) is the matching number part, and zfill fills 0 to the left to fill in the length, for example 01 → 02 instead of 01 → 2.

You can also write a descending, or modify the prefix, for example

Def increase_string_prefix (s, incr_num=1):

"

String self-increment method with numeric prefix "d -", "1-name" self-increment 1-- > "2-name"

Example

-

> s = "1-name"

> increase_string_prefix (s, incr_num=1)

'2murame`

"

Prefix_searched = re.search (r "^ (\ d +) (-)", s)

If prefix_searched:

Prefix_plus_1 = re.sub (

R "^ (\ d +) (-)"

Lambda x: F "{str (int (x.groups () [0]) + incr_num) .zfill (len (x.groups () [0]))} {x.groups () [1]}"

S

)

Else:

Prefix_plus_1 = f "1-{s}"

Return prefix_plus_1

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