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This article mainly explains "how php finds elements that are not repeated in arrays", interested friends may wish to take a look. The method introduced in this paper is simple, fast and practical. Let's take you to learn "how to find elements in an array that are not repeated"!

Methods: 1. Use array_count_values() to count the number of occurrences of elements and return an associative array;2. Traverse the associative array to determine whether the value is 1. If it is 1, take out the corresponding key name. Syntax: "foreach(array as $k=>$v){if($v==1){$r[]=$k;}}".

Operating environment of this tutorial: Windows 7 system, PHP7.1 version, DELL G3 computer

How does PHP find elements that are not duplicated in an array?

In php, you can use the array_count_values() function to find elements in an array that are not duplicated.

The array_count_values() function counts the number of occurrences of all values in an array; if the number is 1, the element is not repeated.

The array_count_values() function returns an associative array whose element keys are the values of the original array and whose key values are the number of times that value appears in the original array.

It can be seen that in the associative array, elements with key value 1 are non-duplicate elements, and the corresponding key name can be obtained.

All you need to do is traverse the associative array using the foreach statement, get the key name of the element with key 1, and assign it to an empty array.

$result=[];foreach($count as $k=>$v){ if($v==1){ $result[]=$k; }}var_dump($result);

At this point, I believe that we have a deeper understanding of "how php finds elements that are not repeated in arrays", so let's actually operate it! Here is the website, more related content can enter the relevant channels for inquiry, pay attention to us, continue to learn!

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