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This article will explain in detail the use of digital correlation functions in VB.NET calculation. The content of the article is of high quality, so the editor shares it for you as a reference. I hope you will have a certain understanding of the relevant knowledge after reading this article.

As soon as the VB.NET programming language appeared, it was favored by the majority of developers by virtue of its powerful functions. It has a variety of applications and a wide range of applications, such as the method of calculating numbers by VB.NET, which is introduced here, which can be easily realized through the application of two functions.

It is important for Visual Basic developers to manipulate strings and perform various string operations. When you need to determine the number of words in a long string, you can use Split, a simple function in VB.NET, to get the desired results.

The Split function allows you to separate long strings into separate words; but if there is more than one space between words, Split returns an incorrect result. To prevent this from happening, you can replace the occurrence of multiple spaces with the Replace function before using Split. Listing A gives an example.

VB.NET calculates number list A

Private Sub CountWords ()

Dim strText As String =

"It's a wonderful world"

Dim iCount As Integer

Do While (strText.IndexOf

(Space (2)) > = 0)

StrTextstrText = strText.

Replace (Space (2), Space (1))

Loop

ICount = Split (strText

Space (1). Length

MsgBox (iCount.ToString ())

End Sub

In this VB.NET numeric example, I created the string strText and set it to a long string with multiple characters. Then, I use the Replace function to replace multiple spaces with a single space. This is done to get the string strText ready so that you can use the Split function and provide the correct results. Next, I input strText into the Split function and get the number of words included in the string strText.

Note: if you skip or comment on the loop used to remove extra spaces, the result is 7 words. After using a loop that removes all excess spaces, the result is correct, four words.

Private Sub CountWords ()

Dim strText As String =

"It's a wonderful world"

Dim iCount As Integer

Do While (strText.IndexOf

(Space (2)) > = 0) strTextstrText

= strText.Replace (Space (2)

Space (1)) Loop

ICount = Split (strText

Space (1). Length MsgBox

(iCount.ToString ())

End Sub

On the VB.NET calculation of the use of digital correlation functions to share here, I hope the above content can be of some help to you, can learn more knowledge. If you think the article is good, you can share it for more people to see.

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