Shulou(Shulou.com)06/01 Report--

The first is to use the decode, a very common way to write:

select sname,sum(decode(course,'language', score,0)) "language",sum(decode(course,' math', score,0)) "mathematics",sum(decode(course,'english', score,0)) "english" from score group by sname;

The second is a function pivot using oracle, which is a column rotation. There is also an unpivot, which is row to column.

select * from (select sname,course,score from score)

pivot(

sum(score)

for course in(

'language' as "language",

'mathematics' as 'mathematics,'

'English' as "English"))

order by sname;

Data source:

SNAME COURSE SCORE

-------------------

Bill Language 80

Bill Math 90

Bill English 92

Jim Language 78

Jim Maths 88

Jim English 98

Comparison of the two results:

SNAME Chinese Mathematics English

------------------------------

Bill 80 90 92

Jim 78 88 98

SNAME Chinese Mathematics English

-------------------------------

Bill 80 90 92

Jim 78 88 98

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