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This article mainly explains "python how to judge whether the elements in an and b are consistent". The content in the article is simple and clear, and it is easy to learn and understand. Please follow the editor's train of thought to study and learn "python how to judge whether the elements in an and b are consistent".

A = "abcd31d111111" b = "3acdb1"

There are a lot of answers to this question online, and the following code is just to throw a brick and attract jade.

Let me briefly say what I think here:

Analysis:

Judge whether the elements are the same, and judge whether the constituent elements are consistent, that is, the repeated elements can be calculated at once.

Method 1:

The way collections are used

A = "abcd31d111111" b = "3acdb1" print (set (a) = = set (b))

Method 2:

Use all ()

1. Judge the length first.

two。 Use python's all as a built-in method

A = "abcd31d111111" b = "3acdb1" long_ = an if len (a) > len (b) else bshort_ = an if len (a) < len (b) else bresult = all ([short_.count (x) for x in long_]) print (result) Thank you for your reading. This is the content of "how python judges whether the elements in an and b are consistent". After the study of this article I believe you have a deeper understanding of how python judges whether the elements in an and b are consistent, and the specific use needs to be verified in practice. Here is, the editor will push for you more related knowledge points of the article, welcome to follow!

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