What happens if the php die function does not pass a parameter
Today, I would like to share with you the relevant knowledge of what happens when the php die function is not transmitted. The content is detailed and the logic is clear. I believe most people still know too much about this knowledge, so share this article for your reference. I hope you can get something after reading this article. Let's take a look.
The php die function will directly terminate the execution program and exit the current script without passing a parameter. The die () function, which outputs a message and exits the current program, accepts an optional parameter that specifies the message or status number written before exiting the script. When the die () function does not pass parameters, you can omit the parentheses after the function and write "die;".
Operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer
Php die () function
The die () function can output a message and exit the current program.
This function accepts an optional argument
Die (message)
The message parameter: specifies the message or status number written before exiting the script; the status number is not written to the output.
The value of the message parameter can be of either string type or int type:
If message is of type string, the function prints the string and exits the current script
If message is of type int, the value will be used as the exit status code and will not be printed.
The value of the exit status code ranges from 0 to 254. note: do not use the exit status code reserved by PHP. The status code 0 is used to successfully abort the program.
If the die function does not pass parameters, and if the message parameter is omitted, the execution program will be terminated directly, the current script will be exited, and no message will be output.
Example:
Tip: if the message parameter is empty (omitted), you can omit the parentheses after the function (such as die;).
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