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Editor to share with you how leetCode prints from 1 to the largest n-digit number. I hope you will get something after reading this article. Let's discuss it together.

First, print from 1 to the maximum number of n digits 1, a brief description of the problem

Enter the number n and print out the n-digit decimal number from 1 to the largest n digits in order. For example, enter 3, then print out 1, 2, 3 all the way up to the maximum 3 digits 999.

2, example description example 1:

Input: n = 1

Output: [1, 2, 3, 4, 5, 6, 7, 8, 9]

Description:

Instead of printing, return a list of integers

N is a positive integer

3, the train of thought of solving the problem

Calculate the data of 10 ^ n, and then use the array to load the data

4, problem solving program public class PrintNumberTest {

Public static void main (String [] args) {

Int nasty 1

Int [] printNumbers = printNumbers (n)

For (int num:printNumbers

) {

System.out.print (num+ "\ t")

}

}

Public static int [] printNumbers (int n) {

If (n = = 0) {

Return new int [] {0}

}

Double length = Math.pow (10, n)-1

Int [] result=new int [(int) length]

For (int I = 0; I

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