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How to implement the error handling Mechanism of Go

2025-04-10 Update From: SLTechnology News&Howtos shulou NAV: SLTechnology News&Howtos > Internet Technology >

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This article mainly introduces the relevant knowledge of "how to realize the Go error handling mechanism". The editor shows you the operation process through the actual case, and the operation method is simple, fast and practical. I hope this article "how to realize the Go error handling mechanism" can help you solve the problem.

Example

Package main

Import (

"fmt"

)

/ / define a DivideError structure

Type DivideError struct {

Dividee int

Divider int

}

/ / implement the API `error`

Func (de * DivideError) Error () string {

StrFormat: = `

Cannot proceed, the divider is zero.

Dividee:% d

Divider: 0

`

Return fmt.Sprintf (strFormat, de.dividee)

}

/ / define the function of `int` type division operation

Func Divide (varDividee int, varDivider int) (result int, errorMsg string) {

If varDivider = = 0 {

DData: = DivideError {

Dividee: varDividee

Divider: varDivider

}

ErrorMsg = dData.Error ()

Return

} else {

Return varDividee / varDivider, ""

}

}

Func main () {

/ / normal situation

If result, errorMsg: = Divide (100,10); errorMsg = "" {

Fmt.Println ("100Compare 10 =", result)

}

/ / an error message will be returned when the divisor is zero

If _, errorMsg: = Divide (100,0); errorMsg! = "" {

Fmt.Println ("errorMsg is:", errorMsg)

}

}

Execute the above program, and the output is as follows:

100 Cannot proceed 10 = 10errorMsg is: Cannot proceed, the divider is zero. Dividee: 100divider: 0 this is the end of the introduction to "how to implement the Go error handling mechanism". Thank you for reading. If you want to know more about the industry, you can follow the industry information channel. The editor will update different knowledge points for you every day.

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