How does LeetCode print from 1 to the maximum number of n digits

This article mainly introduces how LeetCode prints from 1 to the maximum number of n digits, the article is very detailed, has a certain reference value, interested friends must read it!

Topic: enter the number n and print from 1 to the largest n-digit decimal number in order. For example, enter 3, then print 1, 2, 3,., 999

Def printToMaxOfNDigits (n): print 1, 2,..., 99999 (n 9s) can start with 1 and then be added to n 9s by large addition. You can also use the recursive method to implement "" def helper (idx): # Recursive exit is to set the last bit if idx = = n-1: for j in range (n): if number [j]! = '0values: break if number [j] = =' 0entries: Return else: print ('. Join (number [j:])) return for k in range (10): # there are 10 digits available for each bit After the first bit is set, the next bit is set. After setting n bits, number [idx + 1] = str (k) helper (idx + 1) if n < 1: return number = ['0'] * n for i in range (10): # for the first bit There are 10 numbers available number [0] = str (I) helper (0) above is all the contents of the article "how to print from 1 to the largest n digits by LeetCode". Thank you for reading! Hope to share the content to help you, more related knowledge, welcome to follow the industry information channel!