Shulou(Shulou.com)06/01 Report--

This article introduces the relevant knowledge of "what are the methods of generating random passwords in Linux system". In the operation of actual cases, many people will encounter such a dilemma, so let the editor lead you to learn how to deal with these situations. I hope you can read it carefully and be able to achieve something!

1. Use the sha algorithm to encrypt the date and output the first 32 characters of the result:

Date +% s | sha256sum | base64 | head-c 32; echo

The result is as follows:

Ztnimgm0ndi5ogzjmwmxndlhzmjmngm4

two。 Use the embedded / dev/urandom and filter out characters that are rarely used on a daily basis. Here, only the first 32 characters of the result are output:

< /dev/urandom tr -dc _a-z-a-z-0-9 |head -c${1:-32};echo 生成结果如下: pdj0xwz7exd_qb5b27bwwsm1hrf3a7cj 3. 使用openssl的随机函数 openssl rand -base64 32 生成结果如下: ryjwqjltlayex3j7ncbir20h1k/0cnqlneunytscfko= 4. 这种方法类似于之前的urandom，但它是反向工作的 tr -cd '[:alnum:]' < /dev/urandom | fold -w32 | head -n1;echo 生成结果如下: tpgudzf7sqtu4yyw2lvhmuqoziqi87 5. 使用string命令，它从一个文件中输出可打印的字符串 strings /dev/urandom | grep -o '[[:alnum:]]' | head -n 32 | tr -d '\n'; echo 生成结果如下: w4v1iqtkmq8sidd9jxdqnpg8hpmoz8 6. 这是使用urandom的一个更简单的版本 < /dev/urandom tr -dc _a-z-a-z-0-9 | head -c32;echo 生成结果如下: rmdlgspn_bm-izvfwz9bei0rf-jiy6gs 7. 使用非常有用的dd命令 dd if=/dev/urandom bs=1 count=32 2>

/ dev/null | base64-w 0 | rev | cut-b 2-| rev

The result is as follows:

9+0rud4u3hmsdmlgd7j0sf/r09mzfdvbs28w+po2wca

8. You can even generate a password that can be entered with only the left hand.

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