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This article is to share with you about how php can add one points every day. The editor thinks it is very practical, so share it with you as a reference and follow the editor to have a look.

Php realizes the method of adding one points per day: 1. Add a field logintime;2 to the data table and compare the 00:00 zero seconds of the day with the last login time; 3. Through "if ($lastLogintime)"

< $today) {...}"实现积分增加即可。 本文操作环境：Windows7系统，PHP7.4版，Dell G3电脑。 php实现一天多次登录,只积分一次功能： 在网上找了很多的案例，感觉都差不多，有的还比较的繁琐，就自己尝试了一下，如何实现这个功能 实现这个功能我在数据表里面增加了一个字段logintime,表示最后一次的登录时间，然后使用一天中的零时零分零秒和上一次的登录时间进行比较，如果上一次的登录时间大于了这个时间点表示已经登陆过，如果上一次的登录时间小于了这个时间点，则表示第一次登录，增加积分 上代码： // 判断是否是一天中第一次登录// 上一次登陆的时间$lastLogintime = $userinfo['logintime'];// 一天中的零时零分零秒$today = strtotime(date('Y-m-d'));if($lastLogintime < $today) { // 一天中第一次登录增加积分(关联更新) // 注意：使用关联更新数据的时候需要传递两次id $data['id'] = $userinfo['id']; $data['userinfo'] = array( 'points' =>

$userinfo ['points'] + C (' LOGIN'),); $user- > relation (true)-> where (array ('id'= > $userinfo [' id']))-> save ($data);}

It is important to note that you also need to modify the login time:

/ / Update login time and login ip$updateData = array ('id'= > $userinfo [' id'], 'userinfo' = > array (' logintime' = > time (), 'loginip' = > getIP (),)); $user- > relation (true)-> where (array (' id'= > $userinfo ['id']))-> save ($updateData)

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