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This article is about how to use C++ to implement the game of gluttonous Snake. The editor thinks it is very practical, so share it with you as a reference and follow the editor to have a look.

Gluttonous snake game

The keyboard controls the small snake to move up, down, left and right, adding 1 to the length after being late for food; the snake touches itself or the edge of the window and the game fails

Program framework

# include # include # include / / Global variable definition void startup () / initialization function {} void show () / drawing function {} void updateWithoutInput () / / input-independent updates {} void updateWithInput () / / input-related updates {} int main () {startup () / / initialize function, execute while (1) {show () only once; / / draw updateWithoutInput (); / / update updateWithInput () independent of input / / updates related to input} return 0;} draw game maps and snakes

Draw a grid map of the game and use a two-dimensional array Blocks to store information for each grid. Snake information can also be recorded in a two-dimensional array Blocks. Set the element value to 0 to indicate emptiness and draw a gray square; an element value of 1 means a snakehead, and the snake body behind the snakehead is a positive integer such as 2, 3, 4, 5, etc., and draw a colored square

Int I, j for (I = 0; I)

< HEIGHT; i++){ for (j = 0; j < WIDTH; j++) { if (Blocks[i][j] >

0) {setfillcolor (HSVtoRGB (blocks [I] [j] * 10,0.9,1));} else {setfillcolor (RGB (150,150,150)) } fillrectangle (j * BLOCK_SIZE, I * BLOCK_SIZE, (j + 1) * BLOCK_SIZE, (I + 1) * BLOCK_SIZE);}}

The snake moves to the right.

Suppose the initial element value of the little snake is 54321, including 1 snake head and 5432 snake bodies. First, add 1 to all the elements greater than 0 in the two-dimensional array to get 65432; then change the maximum value 6 to 0, that is, remove the original snake tail; finally, change the element on the right side of 2 from 0 to 1, that is, the snake moves to the right

Void moveSnake () {int I, j; for (I = 0; I

< HEIGHT; i++) { for (j = 0; j < WIDTH; j++) { if (Blocks[i][j] >

0) {Blocks [I] [j] +;} int oldTail_i, oldTail_j, oldHead_i, oldHead_j; int max = 0; for (I = 0; I

< HEIGHT; i++) { for (j = 0; j < WIDTH; j++) { if (max < Blocks[i][j]) { max = Blocks[i][j]; oldTail_i = i; oldTail_j = j; } if (Blocks[i][j] == 2) { oldHead_i = i; oldHead_j = j; } } } int newHead_i = oldHead_i; int newHead_j = oldHead_j; newHead_j = oldHead_j + 1; Blocks[newHead_i][newHead_j] = 1; Blocks[oldTail_i][oldTail_j] = 0;}void updateWithoutInput() // 与输入无关的更新{ moveSnake(); Sleep(100);}控制小蛇4个方向移动 变量oldHead_i、oldHead_j存储移动前的蛇头位置，newHead_i、newHead_j存储移动后的蛇头位置。小蛇向上移动，只需把新蛇头的坐标设为旧蛇头的上方即可 newHead_i = oldHead_i - 1; 让玩家用A、S、D、W键控制游戏角色移动，定义字符变量moveDirection表示小蛇运动方向，在moveSnake函数中对其值进行判断，取A向左运动、D向右运动、W向上运动、S向下运动： if (moveDirection == 'A'){ newHead_j = oldHead_j - 1;}else if (moveDirection == 'D'){ newHead_j = oldHead_j + 1;}else if (moveDirection == 'W'){ newHead_i = oldHead_i - 1;}else if (moveDirection == 'S'){ newHead_i = oldHead_i + 1;} 在updateWithInput()函数中获得用户按键输入，如果是A、S、D、W键之一，就更新moveDirection变量，执行moveSnake()函数让小蛇向对应方向移动： void updateWithInput() // 和输入有关的更新{ if (_kbhit()) { char input = _getch(); if (input == 'A' || input == 'S' || input == 'D' || input == 'W') { moveDirection = input; moveSnake(); } }}时间控制的改进 在Sleep()函数运行时，整个程序都会暂停，包括用户输入模块。用户会感觉到卡顿 利用静态变量，将updateWithoutInput()修改如下： void updateWithoutInput() // 与输入无关的更新{ static int waitIndex = 1; waitIndex++; // 每一帧加1 if (waitIndex == 10) { moveSnake(); waitIndex = 1; }} 其中，updateWithoutInput()每次运行时，waitIndex加1，每隔10帧，才执行一次移动函数moveSnake()。这样可在不影响用户按键输入的情况下，降低小蛇的移动速度 失败判断与显示 定义全局变量isFailure表示游戏是否失败，初始化为0： int isFailure = 0; 当小蛇碰到画面边界时，则认为游戏失败；当蛇头与蛇身发生碰撞时，游戏也失败。由于每次只有蛇头是新生成的位置，所以在moveSnake()函数中只需判断蛇头是否越过边界和碰撞： if (newHead_i >

= HEIGHT | | newHead_i

< 0 || newHead_j >

= WIDTH | | newHead_j

< 0 || Blocks[newHead_i][newHead_j] >

0) {isFailure = 1; return;} add the display information after game failure to the show () function: if (isFailure) / / game failure {setbkmode (TRANSPARENT); / / text font transparent settextcolor (RGB (255,0,0)) Settextstyle (80,0,T ("Verdana"); outtextxy (240,220, _ T ("Game failure");}

Add code to updateWithoutInput (), and when isFailure is 1, return directly:

Void updateWithoutInput () / / input-independent updates {if (isFailure) {return;} / /...}

In updateWithInput (), processing occurs only when the keyboard is pressed and isFailure is 0:

Void updateWithInput () / / updates related to input {if (_ kbhit () & & isFailure = = 0) {/ /.}} add food

Add a global variable to record the location of the food:

Int food_i, food_j; initialize the food in the startup () function: void startup () / / initialization function {food_i = rand ()% (HEIGHT-5) + 2; food_j = rand ()% (WIDTH-5) + 2;}

Draw a small green square at the food location in the show () function:

Setfillcolor (RGB (0,255,0)); fillrectangle (food_j * BLOCK_SIZE, food_i * BLOCK_SIZE, (food_j + 1) * BLOCK_SIZE, (food_i + 1) * BLOCK_SIZE)

When the new snakehead touches the food, just keep the original snake tail to increase the length of the snake by 1. When the food is eaten, the food position reappears randomly, and the snake length is increased by 1; when there is no late food, the old snake tail becomes blank, and the snake length remains the same:

Blocks [newHead _ I] [newHead_j] = 1 the position value of the new snakehead is 1if (newHead_i = = food_i & & newHead_j = = food_j) / / if the new snakehead touches the food {food_i = rand ()% (HEIGHT-5) + 2; / / the food re-random position food_j = rand ()% (WIDTH-5) + 2;} else {blocks [oldTail _ I] [oldTail_j] = 0 / / the old snake tail becomes blank} complete code

# include # define BLOCK_SIZE 20 / / A total of 30 cells on the length and width of each cell # define HEIGHT 30 / / A total of 40 cells on the width # define WIDTH 40 / / Global variable definition int Blocks [HEIGHT] [WIDTH] = {0}; char moveDirection;int isFailure = 0 HEIGHT food_i, food_j / / position of food void startup () / / initialization function {int i; Blocks [HEIGHT / 2] [WIDTH / 2] = 1; / / draw snakehead for (I = 1; I 0) {setfillcolor (HSVtoRGB (blocks[ I] [j] * 10,0.9,1));} else {setfillcolor (RGB (150,150,150)) } fillrectangle (j * BLOCK_SIZE, I * BLOCK_SIZE, (j + 1) * BLOCK_SIZE, (I + 1) * BLOCK_SIZE);}} setfillcolor (RGB (0,255,0)); / / Food color is green fillrectangle (food_j * BLOCK_SIZE, food_i * BLOCK_SIZE, (food_j + 1) * BLOCK_SIZE, (food_i + 1) * BLOCK_SIZE) If (isFailure) / / Game failure {setbkmode (TRANSPARENT); / / text font transparency settextcolor (RGB (255,0,0); settextstyle (80,0,T ("Arial")); outtextxy (240,220, _ T ("Game failure");} FlushBatchDraw (); / batch drawing} void moveSnake () {int I, j; for (I = 0; I

< HEIGHT; i++) { for (j = 0; j < WIDTH; j++) { if (Blocks[i][j] >

0) / / greater than 0 is the small snake element {Blocks [I] [j] +;} int oldTail_i, oldTail_j, oldHead_i, oldHead_j; / / Storage Old Snake int max = 0; for (I = 0; I

< HEIGHT; i++) { for (j = 0; j < WIDTH; j++) { if (max < Blocks[i][j]) { max = Blocks[i][j]; oldTail_i = i; oldTail_j = j; } if (Blocks[i][j] == 2) // 旧蛇头 { oldHead_i = i; oldHead_j = j; } } } int newHead_i = oldHead_i; // 设定变量存储新蛇头 int newHead_j = oldHead_j; if (moveDirection == 'A') // 根据用户按键，设定新蛇头的位置 { newHead_j = oldHead_j - 1; } else if (moveDirection == 'D') { newHead_j = oldHead_j + 1; } else if (moveDirection == 'W') { newHead_i = oldHead_i - 1; } else if (moveDirection == 'S') { newHead_i = oldHead_i + 1; } if (newHead_i >

= HEIGHT | | newHead_i

< 0 || newHead_j >

= WIDTH | | newHead_j

< 0 || Blocks[newHead_i][newHead_j] >

0) / / failure condition {isFailure = 1; return;} blocks [newHead _ I] [newHead_j] = 1; / / the position value of the new snakehead is 1 if (newHead_i = = food_i & & newHead_j = = food_j) / / if the new snakehead touches food {food_i = rand ()% (HEIGHT-5) + 2 / / Food re-random location food_j = rand ()% (WIDTH-5) + 2;} else {blocks [oldTail _ I] [oldTail_j] = 0; / / Old Snake tail becomes blank}} void updateWithoutInput () / / input-independent update {if (isFailure) {return;} static int waitIndex = 1; waitIndex++ / / add 1 if per frame (waitIndex = = 10) {moveSnake (); waitIndex = 1;}} void updateWithInput () / / input-related updates {if (_ kbhit () & & isFailure = = 0) {char input = _ getch () If (input = ='A' | | input = ='S' | | input = ='D' | | input = ='W') {moveDirection = input; moveSnake ();} int main () {startup (); / / initialize the function, execute while (1) {show () only once; / / draw updateWithoutInput () / / updates not related to input updateWithInput (); / / updates related to input} return 0;} Thank you for reading! This is the end of the article on "how to use C++ to realize the game of gluttonous snake". I hope the above content can be helpful to you, so that you can learn more knowledge. If you think the article is good, you can share it out for more people to see!

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