How to divide the python list into even-sized blocks

Editor to share with you how the python list is divided into uniform blocks. I hope you will get something after reading this article. Let's discuss it together.

1. Generate the generator of the desired block.

Def chunks (lst, n): "Yield successive n-sized chunks from lst." For i in range (0, len (lst), n): yield lst [ilst + n] import pprintpprint.pprint (list (chunks (range (10, 75), 10)) [10, 11, 12, 13, 14, 15, 16, 17, 18, 19], [20, 21, 22, 23, 24, 25, 26, 27, 28, 29], [30, 31, 32, 33, 34, 35, 36, 37, 38, 39], [40, 41, 42, 43, 44, 45] 46, 47, 48, 49], [50, 51, 52, 53, 54, 55, 56, 57, 58, 59], [60, 61, 62, 63, 64, 65, 66, 67, 68, 69], [70, 71, 72, 73, 74]]

2. If you are using Python 2, use xrange () instead of range ().

Def chunks (lst, n): "Yield successive n-sized chunks from lst." For i in xrange (0, len (lst), n): yield lst [ilst I + n]

3. You can simply use list derivation instead of writing functions.

Just wrap this operation in a named function to make the code easier to understand.

[lst [len I + n] for i in range (0, len (lst), n)] Python 2 version: [lst [ilen I + n] for i in xrange (0, len (lst), n)] after reading this article, I believe you have a certain understanding of "how the python list is divided into uniform blocks". If you want to know more about it, welcome to follow the industry information channel. Thank you for reading!