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This article mainly introduces "how to configure springboot to use FastJson to return Json view information". In daily operation, I believe many people have doubts about how to configure springboot to use FastJson to return Json view information. Xiaobian consulted all kinds of materials and sorted out simple and easy-to-use methods of operation. I hope it will be helpful to answer the question of "how to configure springboot to use FastJson to return Json view information". Next, please follow the editor to study!

The controller layer of Springboot uses the json information returned by @ ResponseBody or @ RestController. By default, Jackson is used to convert JSON. If you want to use fastjson to return json information, you need to add the configuration in the test config. For example:

@ Configuration

Public class demoConfig {

@ Bean

Public HttpMessageConverters httpMessageConverters () {

FastJsonHttpMessageConverter converter = new FastJsonHttpMessageConverter ()

FastJsonConfig fastJsonConfig = new FastJsonConfig ()

FastJsonConfig.setSerializerFeatures (SerializerFeature.BrowserSecure,SerializerFeature.DisableCircularReferenceDetect)

Converter.setFastJsonConfig (fastJsonConfig)

Return new HttpMessageConverters (converter)

}

}

At this point, the study on "how to configure springboot to use FastJson to return Json view information" is over. I hope to be able to solve your doubts. The collocation of theory and practice can better help you learn, go and try it! If you want to continue to learn more related knowledge, please continue to follow the website, the editor will continue to work hard to bring you more practical articles!

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