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2025-04-14 Update From: SLTechnology News&Howtos shulou NAV: SLTechnology News&Howtos > Development >
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This article mainly analyzes the relevant knowledge points of the modular operation of multiplication and summation of large numbers in C language, the content is detailed and easy to understand, the operation details are reasonable, and has a certain reference value. If you are interested, you might as well follow the editor to have a look. Let's go deep into the knowledge of "what the modular luck of multiplication and summation of large numbers in C language is like".
The problem is like the picture above, which is a common mathematical problem in programming or ACM, which is summarized with the experience of predecessors. (development language c)
# include
# define INT64 _ _ int64
INT64 PowerMode (INT64 basenum, INT64 powernum, INT64 modenum) {
/ / calculate basics ^ powernum% modenum
/ / a ^ (2c) = (a ^ c) ^ 2
/ / a ^ (2c+1) = a * ((a ^ c) ^ 2)
/ / for example, when we write b in binary form 13 (10) = 1101 (2)
/ / We operate from low bit to high bit, and each bit can move b to the right. The above example can be transformed into 3 ^ 13 = 3 ^ 1 * 3 ^ 4 * 3 ^ 8.
/ / (ahumb)% p = a% p * b% p% p
/ / (a ^ b)% p = (a% p) ^ b
/ / a ^ 13% m = (a ^ 8 * a ^ 4 * a ^ 1)% m = a ^ 8% m * a ^ 4% m * a ^ 1% m% m
INT64 result = 1
While (powernum) {
If (powernum&1)
Result = result * basenum% modenum
Basenum = basenum * basenum% modenum
Powernum > > = 1
}
Return result
}
INT64 MultiAdd (INT64 countnum, INT64 basenum, INT64 modenum) {
/ / (aqib)% p = (a% p + b% p)% p
/ /
INT64 sum = 0
For (int item0; I
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