Shulou(Shulou.com)06/02 Report--

Java how to operate InputStream, many novices are not very clear about this, in order to help you solve this problem, the following editor will explain in detail for you, people with this need can come to learn, I hope you can gain something.

1. In.available () this method does not guarantee that all streams have arrived

/ / this writing will result in incomplete received data byte [] input = new byte [in.available ()]; in.read (input) when the network requests data.

2. Error reading mode of binary stream

Byte [] buffer = new byte [1024]; BufferedInputStream bis = new BufferedInputStream (in); ByteArrayOutputStream bos = new ByteArrayOutputStream (); while (bis.read (buffer)! =-1) {/ / this writing will cause the buffer array not to be emptied and the data will be more bos.write (buffer) than the original data stream;} byte [] input = bos.toByteArray ()

3. The correct reading method

Int n; byte [] buffer = new byte [1024]; BufferedInputStream bis = new BufferedInputStream (in); ByteArrayOutputStream bos = new ByteArrayOutputStream (); while ((n=bis.read (buffer))! =-1) {bos.write (buffer,0,n); / / guarantee that only the read stream position} byte [] input = bos.toByteArray ()

4. Read the network flow quickly

/ / use off-the-shelf tools to read URL imgUrl = new URL (path); byte [] input = IOUtils.toByteArray (imgUrl). Is it helpful for you to read the above? If you want to know more about the relevant knowledge or read more related articles, please follow the industry information channel, thank you for your support.

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