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This article mainly shows you how to use java to achieve the sum of four numbers, the content is easy to understand, clear, hope to help you solve your doubts, the following let me take you to study and learn "how to use java to achieve the sum of four numbers" this article.

Given an array nums containing n integers and a target value target, it is determined whether there are four elements in nums, such that the values of a + b + c + d are equal to target. Find all quaternions that meet the conditions and do not repeat.

Note:

Duplicate quads cannot be included in the answer.

Example:

Given array nums = [1, 0,-1, 0,-2, 2], and target = 0. The set of quaternions that meet the requirements are: [- 1,0,0,1], [- 2,0,0,0,2]

Parsing:

Here we mainly look at the while loop. Peek () gets the first inserted element in the linked list, but does not remove it. Poll () also gets the first inserted element in the linked list and removes it from the linked list. The condition of the above while loop is easy to understand, because the number of digits of digits is actually the number of digits of each element in the linked list. For example, if digits is 23 is two digits, then the combination of letters is two digits. Remove is the element removed from the head of the linked list and then spliced and then stored in the linked list. First of all, it is necessary to understand that the linked list is inserted at the end and removed from the head. So if the length of remove is equal to the length of digits, then the length of other elements in the linked list must also be equal to the length of digits.

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