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This article mainly introduces how to write a program in c language to count the number 9 in all integers from 1 to 100, which has a certain reference value. Interested friends can refer to it. I hope you will gain a lot after reading this article. Let's take a look at it.

Idea: to determine the number of times 9 appears in an integer, each bit of the integer can be put forward in turn to determine whether it is 9.

Method: for a single digit, the remainder of 10 is itself. Such as: 7, 7, 7.

For a two-digit number, extract a single digit: take the remainder of 10, such as 17 digits 7; extract 10 digits: divided by 10, such as 17 apace 10 digits 1

This allows you to take out every bit of the integer.

The code is as follows:

# includeint main () {int printf sum = 0 for (I = 0 sum++; I < 100 sum +) {sum++; (I% 10 = = 9) / / bring up individual digits, check whether it is 9 {sum++;} int (I / 10 = = 9) / / bring up ten digits, check whether it is 9 {sum++;} printf ("% d\ n", sum); return 0 } Thank you for reading this article carefully. I hope the article "how to write a program in c language and count the number 9 in all integers from 1 to 100" shared by the editor is helpful to everyone. At the same time, I also hope that you will support it and pay attention to the industry information channel. More related knowledge is waiting for you to learn!

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