Shulou(Shulou.com)06/01 Report--

Subnetting is the subnet mask of class A, B and C by default.

The subnet mask is 32-bit binary

The network portion of the corresponding IP address is represented by 1.

The host portion of the corresponding IP address is represented by 0.

IP address and subnet mask do "logical and" (multiply) operation to get network address

{0 and any number are equal to 0}

{1 and any number are equal to any number itself}

This is the way to calculate the network segment.

Understanding of subnetting

Delimit the host bit to the network bit

Homogenized molecular network (divided into 2, 4, 8, 16, etc.)

Formula:

(1) the number of subnets is 2n (n is borrowed)

(2) available IP (number of hosts) per subnet: 2m-2

M = 32-Network bit length (m host bit)

Subnetting again in the subnet

Summary address

For example, 2Vera 192.168.1.0 Compact 24 (1.0 Murray 1.255)-192.168.1.0 Compact 26

Nasty 26-2402

The number of subnets is 22 to 4.

MFG 32-2606

IP:26-2'64-2'62 is available for each subnet.

Broadcast address coefficient: 001111111163

The first network segment:

Network address: 192.168.1.0

Broadcast address: 192.168.1.63

Range: 1.0-1.63

Available ip:1.1-1.62,

Subnet mask = / 26" 11111111.11111111.11111111.11000000

one hundred and ninety two

The second network segment:

Network address: 192.168.1.64

Broadcast address: 192.168.1.127

Range: 1.64-1.127

Available ip:1.65-1.126

Subnet mask = / 26" 11111111.11111111.11111111.11000000

one hundred and ninety two

The third network segment:

Network address: 192.168.1.128

Broadcast address: 192.168.1.191

Range: 1.128-1.191

Available ip:1.129-1.190

Subnet mask = / 26" 11111111.11111111.11111111.11000000192

The fourth network segment:

Network address: 192.168.1.192

Broadcast address: 192.168.1.255

Range: 1.192-1.255

Available ip:1.193-1.254

Subnet mask = / 26" 11111111.11111111.11111111.11000000

one hundred and ninety two

4. Uneven molecular network (calculated from large to small)

For example, the required number of hosts in the network is 100, 50, 25 and 12 respectively.

Formula:

Number of 2m-2 ≥ hosts

Give an IP address, calculate the network address, broadcast address, and available IP address of the IP

192.168.1.200 Universe 27; 10.1.234.67 Universe 20

Such as: 192.168.1.200 Universe 27

192.168.1.20000 11000000.10101000.00000001.110 01000

/ 27011111111.11111111.11111111.11111111.111 00000

Network address: 11000000.10101000.00000001.110 00000

one hundred and ninety two

Broadcast address: 11000000.10101000.00000001.110 11111223

Available ip: 1.193-1.222

Subnet mask: / 27" 255.255.255.11100000" 255.255.255.224

For example, 10.1.234.67 Compact 20

10.1.234.6700001010.00000001.1110 1010.01000011

/ 20,11111111.11111111.111111 0000.00000000

Network address: 00001010.00000001.1110 0000.00000000

0 broadcast address: 00001010.000001.1110 1111.11111111255

Available ip: 10.1.224.1Murray 10.1.239.254

Subnet mask: / 20 = 255.255.240.0

Let me give you a suggestion, just for reference.

May we make progress together on the road of learning!

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