How to find the first non-repeating character from a string by java

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How do I find the first non-repeating character from a string?

For example, the string "Silence Wang Shen Silence II", the first non-repetitive character is "Wang", right? Because "Shen" is repeated, "silent" is repeated.

Public class FindNonRepeatingChar {public static void main (String [] args) {System.out.println (printFirstNonRepeatingChar); System.out.println (printFirstNonRepeatingChar); System.out.println (printFirstNonRepeatingChar);} private static Character printFirstNonRepeatingChar (String string) {char [] chars = string.toCharArray (); List discardedChars = new ArrayList () For (int I = 0; I < chars.length; iTunes +) {char c = chars [I]; if (discardedChars.contains (c)) continue; for (int j = I + 1; j < chars.length; jacks +) {if (c = = chars [j]) {discardedChars.add (c) Break;} else if (j = = chars.length-1) {return c;} return null;}}

The output is as follows:

Wang Mo null

Let's talk about my train of thought:

1) split the string into an array of characters.

2) declare a List and put the duplicate characters in it.

3) the outer for loop, starting with the first character, and if it is already in List, proceed to the next round.

4) the nested for loop, traversing from the next character of the first character (j = I + 1), adds it to the List if it repeats the previous character, and jumps out of the inner loop; if the last (j = = chars.length-1) is not found, it is the first character that does not repeat, right?

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