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This article will explain in detail how Java uses Arrays.sort () to get the maximum value. The editor thinks it is very practical, so I share it with you as a reference. I hope you can get something after reading this article.

Rely on Arrays.sort () implementation

The array can be sorted from small to large according to the Arrays.sort method. After the sorting is completed, the value of the last bit is the maximum value. The implementation code is as follows:

Import java.util.Arrays

Public class ArrayMax {

Public static void main (String [] args) {

Int [] arr = {3,7,2,1,-4}

Int max = findMaxBySort (arr); / / find the maximum value based on Arrays.sort

System.out.println ("Max is:" + max)

}

/ * *

* find the maximum value based on Arrays.sort

* @ param arr Array to be queried

* @ return maximum

, /

Private static int findMaxBySort (int [] arr) {

Arrays.sort (arr)

Return arr [arr.length-1]

}

}

The results of the above procedures are as follows:

The maximum is: 7

This is the end of the article on "how to use Arrays.sort () to maximize Java". I hope the above content can be of some help to you, so that you can learn more knowledge. if you think the article is good, please share it for more people to see.

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