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This article is about how to use removeat to delete nodes in js. The editor thinks it is very practical, so share it with you as a reference and follow the editor to have a look.

1. For the delete operation removeAt, you need to determine the index boundary and the specific location to add.

2. If the node to be deleted is the head of the linked list, simply move the head to the next node. If the list currently has only one node, the next node is null.

Pointing head to the next node is equivalent to setting head to null, and the linked list is empty after deletion. If the node you want to delete is in the middle of the linked list, you need to find the previous node where position is located and point its next pointer to the next node where position is located.

Example

RemoveAt (position) {/ / position cannot exceed the boundary value if (position)

= this.length) return null; let current = this.head; if (position = 0) {this.head = current.next;} else {let previous = this.find (position-1); current = previous.next; previous.next = current.next;} / / subtract the length of the linked list by 1 this.length--; return current.element;} after deletion. Thank you for reading! This is the end of this article on "how to use removeat to delete nodes in js". I hope the above content can be of some help to you, so that you can learn more knowledge. if you think the article is good, you can share it out for more people to see!

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