How to get the Shell script of the directory where the shell script is located

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Simple version

The following is the simplest implementation that can solve most problems, but the drawback is that for soft links, the directory where the soft links are located is displayed.

Lineos:false

The code is as follows:

#! / bin/bash

DIR= "$(cd" $(dirname "$0") "& & pwd)"

Perfect edition

This version solves the problem of using ln-s target linkName to create soft links that cannot correctly fetch real scripts.

Lineos:false

The code is as follows:

#! / bin/bash

SOURCE= "$0"

While [- h "$SOURCE"]; do # resolve $SOURCE until the file is no longer a symlink

DIR= "$(cd-P" $(dirname "$SOURCE") "& & pwd)"

SOURCE= "$(readlink" $SOURCE ")"

[[$SOURCE! = / *]] & & SOURCE= "$DIR/$SOURCE" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located

Done

DIR= "$(cd-P" $(dirname "$SOURCE") "& & pwd)"

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