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An example Analysis of mul Multiplication Operation

2025-03-28 Update From: SLTechnology News&Howtos shulou NAV: SLTechnology News&Howtos > Development >

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Most people do not understand the knowledge points of this "mul multiplication operation case analysis" article, so the editor summarizes the following content, detailed content, clear steps, and has a certain reference value. I hope you can get something after reading this article. Let's take a look at this "mul multiplication operation case analysis" article.

Product of multiplicators

Al 8-bit Operand ax

Ax 16-bit Operand dx:ax

Eax 32-bit Operand edx:eax

Because if our multiplier is an 8-bit Operand, our result exists in the ax register. If it is a 16-bit Operand, our results are stored in dx:ax. If dx is not 0, the carry flag is set.

After executing the mul instruction, we usually check the carry flag. Because we need to know whether the upper half of the product can be safely ignored.

For example:

Mov al, 6h

Mov bl, 10h

Mul bl

Now we check the carry flag cf = 0, then ah we can ignore it, so the result is 60h.

So let's give you another example:

For example:

Mov ax, 6000

Mov bx, 5000

Mul bx

Let's check the carry flag and cf = 1 at this time. So our result is dx:ax, and then our dx = 1E00, ax = 0000, so in the end our product is 1E000000.

The above is about "mul multiplication operation example analysis" of this article, I believe we all have a certain understanding, I hope the editor to share the content to help you, if you want to know more related knowledge, please pay attention to the industry information channel.

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