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This article mainly shows you the "what is the relationship between characters and strings and arrays and pointers in C++", the content is simple and clear, and I hope it can help you solve your doubts. Now let the editor lead you to study and learn the relationship between characters and strings and arrays and pointers in C++.

The string pointer variable itself is a variable that holds the first address of the string. The string itself is stored in a contiguous memory space headed by the first address and ends with\ 0.

Character pointer

1. * a just points to a character.

Examples are as follows:

Case study

# include

# include

Intmain (void) {

Char*a= "bcd"

Printf ("output characters:% c\ n", * a); / * output characters, using "% c" * /

Printf ("output characters:% c\ n", * (aqui1)); / * output characters, using "% c" * /

Printf ("output string:% s\ n", a); / * output string, using "% s"; and a cannot be preceded by an asterisk "*" * /

System ("pause"); / * in order to see the output * /

}

The running results are as follows:

Output character: B

Output character: C

Output string: bcd

2. If a string constant appears in the expression, the value represented is the address of the first character of the string constant. So hello simply represents its address. The original declaration is equivalent to the following declaration:

Char*a

A = "hello"; / * where the string "hello" simply represents the address of its first character * /

Character array

A character array is made up of several array elements, which can be used to hold the entire string. (that is, using an array of characters to store strings).

In C, strings are treated as an array of characters. (not in C++)

The method of initializing character array:

1)。 You can initialize an array of characters with string constants:

Charstr [] = {"Iamhappy"}

Curly braces can be omitted

Charstr [] = "Iamhappy"; # the system automatically joins\ 0

Note: the overall assignment of the above character array can only be used in the initialization of the character array, not in the assignment of the character array, and the assignment of the character array can only assign its elements one by one.

The following assignment method is wrong:

Charstr [20]

Str= "Iamhappy"

Assign values to each element of the character array one by one.

Charstr [10] = {'I'm sorry, I'm sorry.

In C language, you can represent and store strings in two ways:

(1) use a character array to store a string

Charstr [] = "IloveChina"

(2) point to a string with a character pointer

Char*str= "IloveChina"

String output in both representations: printf ("% s\ n", str)

% s means to output a string and give the character pointer variable name str (for the first representation, the character array name is the first address of the character array, which is consistent with the meaning of the pointer in the second), then the system first outputs the character data it points to, and then automatically makes str add 1 automatically to the next character., so, until the end of the string identifier\ 0.

Char*argv: understood as a string

Char**argv: understood as a string pointer

Char*argv []: array of string pointers

Intmain (intargc,char*argv []) this is an example of a typical array name (or pointer array) as a function argument, and there is still no specified size of the shape parameter array.

Sometimes, in order to deal with array elements in the called function, you can set another parameter to pass the number of array elements to be processed. And when using the array name as the function argument, instead of passing the value of the array element to the parameter, the address of the first element of the real parameter group is passed to the shape parameter group, so that the two arrays share the same memory unit for a long time. It is not the same as a variable as a function parameter.

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