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How to solve the BUG of PHP is_subclass_of function

2025-01-18 Update From: SLTechnology News&Howtos shulou NAV: SLTechnology News&Howtos > Development >

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This article mainly introduces "how to solve the BUG of PHP is_subclass_of function". In the daily operation, I believe many people have doubts about how to solve the BUG problem of PHP is_subclass_of function. The editor consulted all kinds of materials and sorted out simple and easy-to-use operation methods. I hope it will be helpful for you to answer the doubt of "how to solve the BUG of PHP is_subclass_of function"! Next, please follow the editor to study!

The role of is_subclass_of:

The copy code is as follows:

Bool is_subclass_of (object object, string class_name)

Returns TRUE if the class to which the object object belongs is a subclass of the class class_name, otherwise returns FALSE.

Note: since PHP 5.0.3, you can also use a string to specify the object parameter (class name).

Examples of use:

The copy code is as follows:

# determine whether $className is a subclass of $type

Is_subclass_of ($className,$type)

There will be a bug for interface before the php5.3.7 version

Bug: https://bugs.php.net/bug.php?id=53727

The copy code is as follows:

Interface MyInterface {}

Class ParentClass implements MyInterface {}

Class ChildClass extends ParentClass {}

# true

Is_subclass_of ('ChildClass',' MyInterface')

# false

Is_subclass_of ('ParentClass',' MyInterface')

Solution:

The copy code is as follows:

Function isSubclassOf ($className, $type) {

/ / if the class to which $className belongs is a subclass of $type, return TRUE

If (is_subclass_of ($className, $type)) {

Return true

}

/ / if php version > = 5.3.7 there is no interface bug, so $className is not a subclass of $type

If (version_compare (PHP_VERSION, '5.3.7percent,' > =') {

Return false

}

/ / if $type is not an interface and there will be no bug, so $className is not a subclass of $type

If (! interface_exists ($type)) {

Return false

}

/ / create a reflection object

$r = new ReflectionClass ($className)

/ / determine whether the class belongs to the $type interface by reflecting objects

Return $r-> implementsInterface ($type)

}

At this point, the study of "how to solve the BUG of PHP is_subclass_of function" is over. I hope to be able to solve your doubts. The collocation of theory and practice can better help you learn, go and try it! If you want to continue to learn more related knowledge, please continue to follow the website, the editor will continue to work hard to bring you more practical articles!

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