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What is the difference between the Java development operator & and & &

2025-04-04 Update From: SLTechnology News&Howtos shulou NAV: SLTechnology News&Howtos > Development >

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This article mainly explains "what is the difference between Java development operator & and & &". The explanation in this article is simple and clear and easy to learn and understand. Please follow Xiaobian's train of thought to study and learn "what is the difference between Java development operator & and & &".

Both & and & & can be used as operators of logical and to represent logical and (and). When the result of expressions on both sides of the operator is true, the whole operation result is true.

Otherwise, as long as one party is false, the result is false. & & also has the function of short circuit, that is, if the first expression is false, the second expression will not be evaluated.

For example, for the if (str! = null & &! str.equals ("")) expression, when str is null, the following expression will not execute, so there will be no NullPointerException. If you change & & to &, a NullPointerException exception will be thrown. If (x + + y > 0) y will grow, If (x + + y > 0) will not grow & it can also be used as a bit operator. When the expression on both sides of the & operator is not of type boolean, & means bitwise and action. We usually use 0x0f to perform the & operation with an integer to get the lowest 4 bit bits of the integer. For example, the result of 0x31 & 0x0f is 0x01

Thank you for your reading, the above is the content of "Java development operator & what is the difference between &". After the study of this article, I believe you have a deeper understanding of what is the difference between the Java development operator & and & &, and the specific use still needs to be verified in practice. Here is, the editor will push for you more related knowledge points of the article, welcome to follow!

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