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Python to generate mine map method is how, many novices are not very clear about this, in order to help you solve this problem, the following editor will explain in detail for you, people with this need can come to learn, I hope you can gain something.

Requirement description

Input: number of rows m, number of columns n, number of mines k

Output: random minesweeping map

The first step, generate maps and random mines

The second step is to fill the grid with no mines, which represents the total number of mines around.

Train of thought

Code implementation

The following two implementations, without numpy and with numpy, are the same.

The number of from random import shuffle# rows, rows, minefields m, n in range k = 5,10, mine symbol, here 9 denotes the initialization sequence of landmine = mine, the total length is landmine before k is mine, k is followed by 0ls = [landmine for _ mine (k)] + [0 for _ mine (m\ n-k)] # disrupt the sequence. To achieve a random effect shuffle (ls) # the sequence of m rows and n columns matrix = [LS [I + j * n] for i in range (n)] for j in range (m)] # for the grid filling number without mines, this number represents the total number of mines around, pay attention to the edge grid Do not cross the boundary for i in range (m): for j in range (n): if matrix [I] [j] = 0: matrix [I] [j] = sum (1 for an in range (max (I-1,0), min (I + 2, m)) for b in range (max (j-1,0), min (j + 2) N)) if matrix [a] [b] = = landmine) # the final result shows [print (v) for v in matrix] import numpy as np# rows, columns, mines m, n, k = 5,10, "landmine symbol" Here, 9 is used to denote landmine = initialize a sequence with a total length of MFN. TopK is a mine, followed by 0ls = [landmine for _ in range (k)] + [0 for _ in range (MFN-k)] print (ls) # to disrupt the sequence. To achieve a random effect np.random.shuffle (ls) print (ls) # m n sequence = > m rows n column matrix matrix = np.reshape (ls, (m, n)) print (matrix) # fill in the grid without mines, this number represents the total number of mines around, pay attention to the edge grid Do not cross the boundary for i in range (m): for j in range (n): if matrix [I] [j] = 0: matrix [I] [j] = sum (1 for an in range (max (I-1,0), min (I + 2, m)) for b in range (max (j-1,0), min (j + 2) N) if matrix [a] [b] = = landmine) # the final result shows that print (matrix) is helpful to you after reading the above content? If you want to know more about the relevant knowledge or read more related articles, please follow the industry information channel, thank you for your support.

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