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Editor to share with you LeetCode how to solve the printing from 1 to the largest n-digit problem, I believe that most people do not know much about it, so share this article for your reference, I hope you can learn a lot after reading this article, let's learn about it!

Title

Enter the number n and print out the n-digit decimal number from 1 to the largest n digits in order. For example, enter 3, then print out 1, 2, 3 all the way up to the maximum 3 digits 999.

Example 1: input: n = 1 output: [1 public int 2, int 3, 4, 5, 6, 7, 8, 9] description: return a list of integers instead of printing n as a positive integer code class Solution {public int [] printNumbers (int n) {int num = (int) Math.pow (10 num)-1; int [] res = new int [num]; for (int I = 0; I < num) ITunes +) {res [I] = iTun1;} return res;}}

Large number printing

Class Solution {int [] res; int nine = 0, count = 0, start, n; char [] num, loop = {'0,1,' 2, 3, 4, 5, 6, 7, 8, 9'}; public int [] printNumbers (int n) {this.n = n Res = new int [(int) Math.pow (10, n)-1]; num = new char [n]; start = n-1; dfs (0); return res;} void dfs (int x) {if (x = n) {String s = String.valueOf (num) .substring (start) If (! s.equals ("0")) res [count++] = Integer.parseInt (s); if (n-start = = nine) start--; return;} for (char I: loop) {if (I = ='9') nine++; num [x] = I; dfs (x + 1);} nine-- }} these are all the contents of the article "how to solve the problem of printing n digits from 1 to the largest number in LeetCode". Thank you for reading! I believe we all have a certain understanding, hope to share the content to help you, if you want to learn more knowledge, welcome to follow the industry information channel!

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