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Use object deconstruction to simulate named parameters

If you need to pass a series of options as arguments to the function, you may prefer to use an object (Object) to define the Config.

DoSomething ({foo: 'Hello', bar:' Heymilk, baz: 42}); function doSomething (config) {const foo = config.foo! = = undefined? Config.foo: 'Hi'; const bar = config.bar! = = undefined? Config.bar: 'Yoshiyama; const baz = config.baz! = = undefined? Config.baz: 13; / /.}

This is an old but effective method that simulates named parameters in JavaScript. However, the way to deal with config in doSomething is a bit cumbersome. In ES2015, you can use object deconstruction directly.

Function doSomething ({foo = 'Hi', bar =' Yoshiyama, baz = 13}) {/ /...}

If you want this parameter to be optional, it's also simple.

Function doSomething ({foo = 'Hi', bar =' Yoyed parameters, baz = 13} = {}) {/ /.} above is all the content of the article "how JavaScript uses object deconstruction to simulate named parameters". Thank you for reading! I believe we all have a certain understanding, hope to share the content to help you, if you want to learn more knowledge, welcome to follow the industry information channel!

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