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Editor to share with you how to solve the problem of alternating printing FooBar with leetcode multithreading, I believe most people do not know much about it, so share this article for your reference. I hope you will gain a lot after reading this article. Let's go to know it together.

We provide a class for the title: class FooBar {public void foo () {for (int I = 0; I < n; iTunes +) {print ("foo");}} public void bar () {for (int I = 0; I < n; iTunes +) {print ("bar");} two different threads will share a FooBar instance. One thread will call the foo () method, and the other thread will call the bar () method. Please design a modification program to ensure that "foobar" is output n times. Source: LeetCode link: https://leetcode-cn.com/problems/print-foobar-alternately copyright belongs to the collar buckle network. For commercial reprint, please contact official authorization. For non-commercial reprint, please indicate the source. Answer class FooBar {private int n; ReentrantLock lock = new ReentrantLock (); Condition fooCnd = lock.newCondition (); Condition barCnd = lock.newCondition (); boolean foo = true; public FooBar (int n) {this.n = n;} public void foo (Runnable printFoo) throws InterruptedException {lock.lock (); try {for (int I = 0; I < n) If (! foo) {fooCnd.await ();} foo = false; / / printFoo.run () outputs "foo". Do not change or remove this line. PrintFoo.run (); barCnd.signal ();}} finally {lock.unlock ();}} public void bar (Runnable printBar) throws InterruptedException {lock.lock (); try {for (int I = 0; I < n) ) {if (foo) {barCnd.await ();} foo = true; / / printBar.run () outputs "bar". Do not change or remove this line. PrintBar.run (); fooCnd.signal ();}} finally {lock.unlock ();}

Here, ReentrantLock's condition is used for conditional control.

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