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This article mainly introduces "C++ why preference is given to default parameters rather than overload", in daily operation, I believe many people in C++ why preference is given to default parameters rather than overload problems have doubts, small make up all kinds of information, sort out simple and easy to use operation methods, hope to answer "C++ why preference is given to default parameters rather than overload" doubts helpful! Next, please follow the small series to learn together!

F.51: If possible, default parameters are preferred over overloaded Reason

Default parameters simply provide different interfaces for the same implementation. There is no guarantee that all overloaded functions will be implemented with the same semantics. This duplication can be avoided by using default parameters.

Note:

There is a choice between using default argument and overloading when the alternatives are from a set of arguments of the same types. For example:

There is one case where you really need to choose between using default parameters and overloading: the difference between different interfaces comes from a series of parameters that have the same type.

void print(const string& s, format f = {});

as opposed to

rather than

void print(const string& s); // use default formatvoid print(const string& s, format f);

There is not a choice when a set of functions are used to do a semantically equivalent operation to a set of types. For example:

Overloading should be used when a series of functions perform semantically equivalent operations on different types. For example:

void print(const char&);void print(int);void print(zstring)

Enforcement

When a series of overloads have common prefix parameters (e.g.:f(int), f(int, const string&),f(int, const string&, double)). (Note: If there is too much noise in practice (objection), review this rule.)

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